Daily Practice Questions
6 questions across multiple subjects, with detailed explanations and study tips.
📝 Questions
📖 SAT Reading & Writing
Hard
If x + 3 = y and xy = 40, what is the sum of x and y , given that both x and y are positive?
- A. 5
- B. 8
- C. 13 ✓
- D. 15
Explanation: Substitute $y$ with $(x + 3)$ in the second equation to get $x(x + 3) = 40$, which simplifies to the quadratic $x^2 + 3x - 40 = 0$. Factoring this gives $(x + 8)(x - 5) = 0$, yielding solutions $x = -8$ or $x = 5$; since $x$ must be positive, we select $x = 5$. Substituting $x = 5$ back into the first equation gives $y = 8$, so the sum $x + y$ is $5 + 8 = 13$.
🧪 AP Chemistry
Hard
Three 20.00 mL samples of approximately 0.10 M p -cresol, CH _{3} C _{6} H _{4} OH, K _{a} = 6.7 × 10 ^{-} ^{11} were removed from a container and placed in separate 250 mL flasks. The samples were titrated with standard 0.1025 M sodium hydroxide, NaOH, solution. Thymolphthalein was the acid–base indicator used in the titration. The samples required 21.75, 22.38, and 31.75 mL to reach the endpoint. Which of the following might explain why the third sample required significantly more of the base to reach the endpoint?
- A. The indicator was added too soon.
- B. The wrong indicator was used.
- C. There was an acid contaminating the unclean flask. ✓
- D. There was a base contaminating the unclean flask.
Explanation: C —An acid contaminant must be present, and the excess acid would require additional base to titrate this acid in addition to the p -cresol. Do not be distracted by the “OH” in phenol—it has a K _{a} ; therefore, it must be an acid. The key is to recognize the principles (an acid has a K _{a} , and in situations like this, all acids will behave the same). The use of an organic compound is irrelevant as you are being asked about acid–base reactions, not organic chemistry.
🧬 AP Biology
Medium
During which stage of mitosis do the centromeres of chromosomes attach to spindle fibers and line up in a single column in the center of the cell?
- A. prophase
- B. metaphase ✓
- C. anaphase
- D. telophase
Explanation: In metaphase, the centromeres of each chromosome attach to spindle fibers from opposite poles, allowing the chromosomes to align neatly in a single column at the cell's equator. This alignment ensures that sister chromatids are equally positioned before being pulled apart in the subsequent anaphase stage. Prophase involves chromosome condensation and spindle formation but not this specific alignment, while anaphase and telophase occur after the chromosomes have already lined up.
📝 ACT Prep
Easy
The author believes that the origins of religion:
- A. are extremely easy to ascertain and understand.
- B. should not be questioned by historians because religion is fundamental to civilized life.
- C. are directly tied to apelike subhuman species.
- D. should be the subject of serious historical inquiry. ✓
Explanation: The author argues that religion is a fundamental aspect of human history and civilization, implying that its origins warrant rigorous investigation rather than dismissal or simplification. Choice (J) correctly reflects this stance by suggesting that the development of religious thought deserves serious historical inquiry. In contrast, choices (F) and (G) are incorrect because they suggest the origins are either trivial to understand or beyond questioning, which contradicts the author's call for scholarly analysis.
🎓 GRE Prep
Medium
The diagonal of a square of side 4 is
- A. less than 4
- B. equal to 4
- C. greater than 4 but less than 5 ✓
- D. greater than 5
Explanation: The diagonal of a square of side 4 is $4\sqrt{2}$, which is approximately 5.66. So, Quantity B is larger.
⚛️ AP Physics C
Easy
A particle is released from rest at point A . The figure shows the potential energy of the particle as a function of position. If no nonconservative forces are present, which of the following statements is true?
- A. The particle oscillates between points B and F .
- B. The particle cannot reach point G . ✓
- C. The particle moves in simple harmonic motion.
- D. The particle experiences no force at points C , D , and E .
- E. The particle’s speed is maximized at point E .
Explanation: Since no nonconservative forces act, total mechanical energy is conserved: $E_{tot} = K + U$. Released from rest at A, $E_{tot} = U_A$. At point G, $U_G > U_A$, so reaching G would require $K < 0$, which is impossible. Thus, the particle cannot reach G. Option (D) is incorrect because $F = -dU/dx$ is zero only at local extrema (like C and E), not at the inflection point D.
💡 Study Tips
📖 Connect new concepts to what you already know
Learning sticks better when you link new information to existing knowledge. Ask yourself: 'What does this remind me of?' or 'How does this relate to what I learned last week?'
🎯 Time yourself on practice tests
Practicing under timed conditions builds your pacing instincts for test day. If you consistently run out of time on a section, adjust your strategy: spend less time on hard questions and secure the ones you know.
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