📖 AP Physics C
AP Physics C Practice
AP Physics C practice questions with explanations
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📝 Sample Questions
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Hard
The uniform electric field established between the parallel plates of a capacitor has magnitude E . A particle with a charge of magnitude q is released (initially at rest) somewhere between the plates and allowed to move a distance d under the influence of the capacitor’s electric field. What is the change in the particle’s electrostatic potential energy?
- A. Δ U = q ^{2} Ed
- B. Δ U = − q ^{2} Ed
- C. Δ U = qEd
- D. Δ U = − qEd ✓
- E. none of the above
Explanation: The change in electrostatic potential energy ($\Delta U$) is defined as the negative of the work done by the electric field on the charge, expressed as $\Delta U = -W$. Since the constant electric force $F = qE$ acts over a displacement $d$ in the direction of the field, the work done is $W = Fd = q
Hard
If the angular velocity of a disk is given in rads by the equation ω ( t ) = 9 + 3 t , what is the disk’s angular displacement between t = 0 and t = 1 s?
- A. 0.75 rad ✓
- B. 8.25 rad
- C. 9 rad
- D. 10.5 rad
- E. 18 rad
Explanation: The angular displacement $\Delta \theta$ is the definite integral of the angular velocity function $\omega(t)$ over the given time interval, calculated as $\int_{0}^{1} (9 + 3t) \, dt$. Evaluating this integral yields $[9t + \frac{3}{2}t^2]_0^1 = 9(1) + 1.5(1)^2 - 0 = 10.5$ rad. Since the provided c
Hard
A mass is pulled up a frictionless incline by a force applied parallel to the incline. The change in the object’s kinetic energy is equal to which of the following?
- A. the negative of the change in potential energy
- B. the work done by gravity
- C. the work done by the applied force ✓
- D. the work done by the applied force minus the work done by gravity
- E. the work done by the applied force plus the work done by gravity
Explanation: This question tests the Work-Energy Theorem, which states that the net work done on an object equals its change in kinetic energy ($W_{net} = \Delta K$). Since the incline is frictionless and the force is applied parallel to the motion, the only forces doing work are the applied force (positive work
Easy
The magnetic field created by the two wires shown at point A in the figure is B _{0} (pointing out of the page), and the two wires carry identical currents in the same direction. Which of the following is true?
- A. Both wires carry a current of 4 π d /3 μ _{0} toward the top of the page.
- B. Both wires carry a current of 4 π d /3 μ _{0} toward the bottom of the page.
- C. Both wires carry a current of 4 π dB _{0} / μ _{0} toward the top of the page. ✓
- D. Both wires carry a current of 4 π dB _{0} / μ _{0} toward the bottom of the page.
- E. It is impossible for the wires to produce a magnetic field pointing perpendicular to the page.
Explanation: Each wire produces a magnetic field at point A given by the Biot-Savart law for a long straight wire, $B = \frac{\mu_0 I}{2\pi d}$. Since the currents are identical and in the same direction, the fields add constructively. The total field is $B_0 = 2 \left( \frac{\mu_0 I}{2\pi d} \right) = \frac{\mu
Easy
A dielectric material is inserted between the plates of an isolated charged capacitor. Which of the following is true?
- A. The potential energy of the capacitor increases.
- B. The charge of the capacitor decreases.
- C. The capacitance of the capacitor decreases.
- D. The voltage of the capacitor increases.
- E. none of the above ✓
Explanation: Since the capacitor is isolated, its charge $Q$ remains constant when a dielectric is inserted. Inserting a dielectric increases the capacitance $C$, which causes the voltage $V$ to decrease (since $V = Q/C$) and the stored potential energy ($U = Q^2/2C$) to decrease. Because options (A), (B), (C),
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