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GRE practice questions covering Verbal Reasoning and Quantitative Reasoning

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📝 Sample Questions

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Easy
A bookstore will only order books that come in complete cases. Each case has 150 books and costs $1,757. Quantity A Quantity B The number of books that can be ordered for $10,550 The number of books that can be ordered for $12,290
  1. A. Quantity A is greater.
  2. B. Quantity B is greater. ✓
  3. C. The two quantities are equal.
  4. D. The relationship cannot be determined from the information given.
Explanation: Each case costs $1,757 and contains 150 books. For $10,550: floor(10550 / 1757) = 6 cases (since 6×1757=10,542), giving 6×150=900 books. For $12,290: floor(12290 / 1757) = 6 cases? Wait: 7×1757=12,299 >12,290, so only 6 cases → 900 books. But wait: 1757×6=10,542; 1757×7=12,299 which exceeds $12,290.
Medium
6(10)^n > 60,006 n 6
  1. A. Quantity A is greater. ✓
  2. B. Quantity B is greater.
  3. C. The two quantities are equal.
  4. D. The relationship cannot be determined from the information given.
Explanation: We are given 6(10)^n > 60,006. Dividing both sides by 6 gives (10)^n > 10,001. Since 10^4 = 10,000 < 10,001 and 10^5 = 100,000 > 10,001, n must be at least 5. So Quantity A (n) is ≥5, and Quantity B is 6. But n could be 5 or greater — if n=5, A < B; if n=6, A = B; if n>6, A > B. Wait — correction: 1
Medium
The circle shown has center T. The measure of angle TVU is 60°. If the circle has a radius of 3, what is the length of segment RS?
  1. A. 2 ✓
  2. B. 3
  3. C. 2√3
  4. D. 3√2
Explanation: Since the radius $TV = 3$ and $\angle TVU = 60^\circ$, triangle $TVU$ is equilateral, making chord $UV = 3$. Segment $RS$ is perpendicular to radius $TV$ at its midpoint because it bisects the central angle of an equilateral triangle formed by radii $TR$ and $TS$ (where $\angle RTS = 60^\circ$). In
Medium
A customer service center had z inbound calls on hold. During the next minute, one-third of those calls were answered but 15 new calls were placed on hold so that 35 callers were then holding. Quantity A: z Quantity B: 33
  1. A. Quantity A is greater.
  2. B. Quantity B is greater.
  3. C. The two quantities are equal. ✓
  4. D. The relationship cannot be determined from the information given.
Explanation: Initially there were z calls. After one-third are answered, 2z/3 remain on hold. Then 15 new calls are added: total = (2z/3) + 15. This equals 35, so (2z/3) + 15 = 35 → (2z/3) = 20 → z = 30. So Quantity A is 30, Quantity B is 33 → Quantity B is greater? Wait: recheck: (2z/3) + 15 = 35 → 2z/3 = 20 →
Medium
Solve the system of equations: 3a - 2b = 9 and 5a + 3b = 34. Compare a and b.
  1. A. Quantity A is greater. ✓
  2. B. Quantity B is greater.
  3. C. The two quantities are equal.
  4. D. The relationship cannot be determined from the information given.
Explanation: If you tried to solve the system of equations by substitution, because of the coefficients of a and b, you would wind up with fractions, so use combination instead. Start by rearranging the second equation to get 5a + 3b = 34. Make the coefficients of b the same in both equations by multiplying the

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